(PHP 5, PHP 7)
strripos — Find the position of the last occurrence of a case-insensitive substring in a string
$haystack
, string $needle
[, int $offset = 0
] )
Find the numeric position of the last occurrence of
needle in the haystack string.
Unlike the strrpos(), strripos() is case-insensitive.
haystackThe string to search in.
needle
If needle is not a string, it is converted
to an integer and applied as the ordinal value of a character.
offsetIf specified, search will start this number of characters counted from the beginning of the string. If the value is negative, search will instead start from that many characters from the end of the string, searching backwards.
Returns the position where the needle exists relative to the beginnning of
the haystack string (independent of search direction
or offset).
Also note that string positions start at 0, and not 1.
Returns FALSE if the needle was not found.
Această funcție poate întoarce valoarea Boolean FALSE, dar poate de
asemenea întoarce o valoare non-Boolean care evaluează în FALSE. Vă rugăm să
citiți secțiunea despre tipul Boolean
pentru informații suplimentare. Utilizați
operatorul === pentru a
verifica valoarea întoarsă de această funcție.
Example #1 A simple strripos() example
<?php
$haystack = 'ababcd';
$needle = 'aB';
$pos = strripos($haystack, $needle);
if ($pos === false) {
echo "Sorry, we did not find ($needle) in ($haystack)";
} else {
echo "Congratulations!\n";
echo "We found the last ($needle) in ($haystack) at position ($pos)";
}
?>
Exemplul de mai sus va afișa:
Congratulations! We found the last (aB) in (ababcd) at position (2)